Stack in C++

#include<iostream.h>

#include<conio.h>

int max=7;

int t=0;



class stack

{

                int s[7];

              public:

             void push(int);

            void pop();

            void top();

           void empty();

            void show();

};


void stack::push(int y) //Push Operation

{

if(t<max)

 {

  t=t+1;

  s[t]=y;

 }

else

cout<<endl<<"stack overflows..."<<endl;

}


void stack::pop() //Pop Operation

{

int item;

if(t>=0)

 {

  t=t-1;

  item=s[t+1];

  cout<<endl<<"popped item >>"<<item<<endl;

 }

 else

 cout<<endl<<"stack underflows"<<endl;

}



void stack::top() //To find the top of the stack

{

if(t>=0)

cout<<endl<<"topmost element >> "<<s[t]<<endl;

else

cout<<endl<<"stack underflows..."<<endl;

}


void stack::empty() //To check if the stack is empty

{

if(t<0)

cout<<endl<<"stack is empty..."<<endl;

else

cout<<endl<<"stack is not empty..."<<endl;

}


void main()

{

int a,x;

stack s1;

clrscr();

do

{

cout<<"enter an option..."<<endl<<"1-push"<<endl<<"2-pop"<<endl<<"3-top"<<endl<<"4-empty"<<endl;

cout<<"5-end"<<endl;

cin>>a;

cout<<endl;

switch(a)

{

case 1:

{

cout<<endl<<"enter a value  >> "<<endl;

cin>>x;

s1.push(x);

}

break;

case 2:

s1.pop();

break;

case 3:

s1.top();

break;

case 4:

s1.empty();

break;

}

}

while(a!=5);

getch();

}

Basic error handling in vb.NET for inserting data into database

Try
    conn.Open()

    Dim cmd As New OracleCommand
    cmd.Connection = conn
    cmd.CommandText = "select dname from dept where deptno = " + TextBox1.Text
    cmd.CommandType = CommandType.Text

    If dr.Read() Then
        Label1.Text = dr.Item("dname") ' or use dr.Item(0)
    End If
Catch ex As Exception ' catches any error
    MessageBox.Show(ex.Message.ToString())
Finally
    ' In a real application, put cleanup code here.
End Try




Catch ex As OracleException ' catches only Oracle errors
    Select Case ex.Number
        Case 1
            MessageBox.Show("Error attempting to insert duplicate data.")
        Case 12545
            MessageBox.Show("The database is unavailable.")
        Case Else
            MessageBox.Show("Database error: " + ex.Message.ToString())
    End Select







Catch ex As Exception ' catches any error
    MessageBox.Show(ex.Message.ToString())

catch (Exception ex) // catches any error not previously caught
{
    MessageBox.Show(ex.Message.ToString());
}

Unique Random number generator in vb.net

//hey guys here is my new program in vb.NET which generates unique 20 random Numbers.
Public Class Form1
    Dim generator As New Random
    Dim arr(20) As Integer
    Dim num As Integer = 0
    Dim i As Integer = 1
    Dim k As Integer = 0
    Dim x As Boolean

    Public Sub btngenerate_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btngenerate.Click

        numshow()


    End Sub


    Private Sub numshow()
        If k < 20 Then
            num = generator.Next(1, 21)
            x = check()
            If x = True Then

                arr(i) = num
                Label1.Text = arr(i).ToString
                i = i + 1
                k = k + 1
            Else

                numshow()
                num = 0
            End If


        Else
            MessageBox.Show("no more")
        End If

    End Sub
    Private Function check() As Boolean
        Dim l = i - 1
        For j As Integer = 1 To l

            If arr(j) = num Then
                Return False
            End If
        Next
        Return True

    End Function
End Class



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